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跳至主要內容如何判斷一個整數是不是三的次方!
給予一個整數並判斷它是否二的次方，除了使用迴圈，你還想的到其他做法嗎?
同構，簡單來說就是字元之間的對應。要判斷兩個字串中是否同構，就要進行一個簡單的對應去確認!
看起來是一題可以靠著簡單的for迴圈完成的題目，那又有甚麼要特別注意的嗎?
這一題，我們必須確認是否每個英文字母都跟其中一個單字是一對一的關係
反轉整個鏈結串列，如何在使用較少額外空間下達成這個目標
遍歷一顆二元樹通常有三種方法，差異在於順序。這一次講到的就是其中的中序遍歷。
在陣列中尋找只出現一次的數字
選定特定的整數，並移除陣列中對應的元素，目標是使陣列的長度減至一半以下
【Blind 75】 尋找已排序且旋轉過的陣列中的最小值? 聽起來很簡單啊! 直接For loop暴力執行不能嗎? 什麼! 居然有時間複雜度的限制!!!
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