Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
if the last digit of the number is non-zero, she decreases the number by one;
if the last digit of the number is zero, she divides the number by 10 (i.e. removes the last digit).
You are given an integer number n. Tanya will subtract one from it k times. Your task is to print the result after all k subtractions.
It is guaranteed that the result will be positive integer number.
給予你一個整數數字 n。 Tanya 會對這個數字進行 k次的減法,你的任務就是要印出 k 次之後的結果。
答案保證是一個正整數。
輸入
The first line of the input contains two integer numbers n and k (2≤ n ≤109, 1≤ k ≤50) — the number from which Tanya will subtract and the number of subtractions correspondingly.
第一行輸入包含了兩個整數數字 n 以及 k
輸出
Print one integer number — the result of the decreasing n by one k times.
It is guaranteed that the result will be positive integer number.
印出一個整數 — n 經過 k 次減法後的結果。
答案保證是一個正整數。
範例
輸入
512 4
輸出
50
輸入
1000000000 9
輸出
1
筆記
The first example corresponds to the following sequence: 512→511→510→51→50
第一個範例的逐步結果會是這樣 : 512→511→510→51→50
解題思路
應該沒什麼困難的地方,跑個迴圈並按照給定的規則來計算答案就好
C#解決方案
方案1
string[]arr = Console.ReadLine().Split(' '); //split by space
int n = int.Parse(arr[0]);
int k = int.Parse(arr[1]);
for(int i=0;i<k;i++){
if(n%10==0){
n = n/10;
}
else {
n = n-1;
}
}
Console.WriteLine(n);
Java解決方案
方案1
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String[] arr = scanner.nextLine().split(" ");
int n = Integer.parseInt(arr[0]);
int k = Integer.parseInt(arr[1]);
for(int i=0;i<k;i++){
if(n%10==0){
n = n/10;
}
else {
n = n-1;
}
}
System.out.println(n);
}
}
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