Dr. Bruce Banner hates his enemies (like others don’t). As we all know, he can barely talk when he turns into the incredible Hulk. That’s why he asked you to help him to express his feelings.
Hulk likes the Inception so much, and like that his feelings are complicated. They have n layers. The first layer is hate, second one is love, third one is hate and so on…
For example if n = 1, then his feeling is “I hate it” or if n = 2 it’s “I hate that I love it”, and if n = 3 it’s “I hate that I love that I hate it” and so on.
例如,如果n = 1,那麼他的感受是”I hate it”;如果n = 2,那麼他的感受是”I hate that I love it”;如果n = 3,那麼他的感受是”I hate that I love that I hate it”,以此類推。
請幫助布魯斯博士。
輸入
The only line of the input contains a single integer n (1 ≤ n ≤ 100) — the number of layers of love and hate.
唯一一行的輸入包含了一個整數 n (1 ≤ n ≤ 100) — 愛跟恨共有幾層。
輸出
Print Dr.Banner’s feeling in one line.
在一行中印出班納博士的感受。
範例
輸入
1
輸出
I hate it
輸入
2
輸出
I hate that I love it
輸入
3
輸出
I hate that I love that I hate it
解題思路
從題目中,我們可以發現一定是從 I hate 開頭,然後不斷交換,最後一次結尾則不是that而是it。
故,我們可以透過迴圈搭配簡單的三元不等式來判斷目前所在層數
然後一如往常,使用了StringBuilder 而不是string來提高部分字串效能
C#解決方案
方案1
using System.Text;
int n = int.Parse(Console.ReadLine());
var result = new StringBuilder();
for(int i=0; i<n-1; i++){
result.Append(i%2==0?"I hate that ":"I love that ");
}
result.Append(n%2==0?"I love it":"I hate it");
Console.WriteLine(result.ToString());
Java解決方案
方案1
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
StringBuilder result = new StringBuilder();
for(int i=0; i<n-1; i++){
result.append(i%2==0?"I hate that ":"I love that ");
}
result.append(n%2==0?"I love it":"I hate it");
System.out.println(result.toString());
}
}
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