«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every k-th dragon got punched in the face with a frying pan. Every l-th dragon got his tail shut into the balcony door. Every m-th dragon got his paws trampled with sharp heels. Finally, she threatened every n-th dragon to call her mom, and he withdrew in panic.
How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of d dragons?
Input
Input data contains integer numbers k, l, m, n and d, each number in a separate line (1 ≤ k, l, m, n ≤ 10, 1 ≤ d ≤ 105).
Output
Output the number of damaged dragons.
Examples
Input
1 2 3 4 12
Output
12
Input
2 3 4 5 24
Output
17
Note
In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed.
Solution
In our solution, we check if any of the conditions equals 1, then we output the count of all dragons.
C# Solution
Solution1
int k = int.Parse(Console.ReadLine());
int l = int.Parse(Console.ReadLine());
int m = int.Parse(Console.ReadLine());
int n = int.Parse(Console.ReadLine());
int d = int.Parse(Console.ReadLine());
if(k==1 || l==1 || m==1 || n==1){
Console.WriteLine(d);
}
else
{
int cnt = 0; // number of damaged dragons
for(int i=1; i<=d ;i++){
if (i % k == 0 || i % l == 0 || i % m == 0 || i % n == 0)
{
cnt++;
}
}
Console.WriteLine(cnt);
}
for(int i=1; i<=d ;i++) : This loop helps us determine how many dragons suffered damage within the range from 1 to d.
Java Solution
Solution1
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int k = Integer.parseInt(scanner.nextLine());
int l = Integer.parseInt(scanner.nextLine());
int m = Integer.parseInt(scanner.nextLine());
int n = Integer.parseInt(scanner.nextLine());
int d = Integer.parseInt(scanner.nextLine());
if (k == 1 || l == 1 || m == 1 || n == 1) {
System.out.println(d);
}
else
{
int cnt = 0; // number of damaged dragons
for (int i = 1; i <= d; i++)
{
if (i % k == 0 || i % l == 0 || i % m == 0 || i % n == 0)
{
cnt++;
}
}
System.out.println(cnt);
}
}
}
Conclusion
Poor dragons~
🧡If my solution helps, that is my honor!
🧡You can support me by sharing my posts, thanks you~~
✅If you got any problem about the explanation or you need other programming language solution, please feel free to let me know !!
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