Codeforces 1807A Plus or Minus Solution & Explanation

Difficulty : 800

Problem Description

You are given three integers a, b, and c such that exactly one of these two equations is true:

• a+b=c
• a−b=c

Output + if the first equation is true, and – otherwise.

Input

The first line contains a single integer t (1≤t≤162) — the number of test cases.

The description of each test case consists of three integers a, b, c (1≤a,b≤9, −8≤c≤18). The additional constraint on the input: it will be generated so that exactly one of the two equations will be true.

Output

For each test case, output either + or – on a new line, representing the correct equation.

Examples

Note

In the first test case, 1+2=3.

In the second test case, 3−2=1.

In the third test case, 2−9=−7. Note that c can be negative.

Solution

We can use a for loop and a simple equality statement to check the answer.

C# Solution

Solution1

int t = int.Parse(Console.ReadLine());

for(int i=0; i<t; i++){
    int[] arr = Console.ReadLine().Split(' ').Select(int.Parse).ToArray();
    if(arr[0]+arr[1]==arr[2]){
        Console.WriteLine("+");
    }   
    else{
        Console.WriteLine("-");   
    }
}

Conclusion

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The problem link : Problem – 1807A – Codeforces

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