Codeforces 71A Way Too Long Words Solution & Explanation

Difficulty : 800

Problem Description

Sometimes some words like “localization” or “internationalization” are so long that writing them many times in one text is quite tiresome.

Let’s consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.

This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn’t contain any leading zeroes.

Thus, “localization” will be spelt as “l10n”, and “internationalization» will be spelt as “i18n”.

You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.

Input

The first line contains an integer n (1 ≤ n ≤ 100). Each of the following n lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.

Output

Print n lines. The i-th line should contain the result of replacing of the i-th word from the input data.

Examples

Solution

In this problem, we are given a set of strings as input. If a string’s length is greater than 10, we transform it into another string.

C# Solution

Solution1

int n = int.Parse(Console.ReadLine());

for(int i=0;i<n;i++){
    string str = Console.ReadLine();
    if(str.Length>10){
        Console.WriteLine(str[0]+(str.Length-2).ToString()+str[str.Length-1]);
    } else {
        Console.WriteLine(str);
    }
}

Java Solution

Solution1

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine());

        for (int i = 0; i < n; i++) 
        {
            String str = scanner.nextLine();
            if(str.length()>10){
                System.out.println(str.charAt(0)+String.valueOf(str.length()-2)+str.charAt(str.length()-1));
            } else {
                System.out.println(str);
            }
        }
    }
}

Python3 Solution

Solution1

n = int(input())

for i in range(n):
    x = input()
    if (len(x) > 10):
        print(x[0] + str(len(x)-2) + x[len(x)-1])
    else:
        print(x)

python input() will get a string object, so it need to be convert to integer

JavaScript Solution

Solution1

var n = readline();

for (var i = 0; i < n; i++) {
    var str = readline();
    if (str.length > 10) {
        print(str[0] + (str.length - 2) + str[str.length - 1]);
    } else {
        print(str);
    }
}

Conclusion

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The problem link : Problem – 71A – Codeforces

You can find the solution for the next problem here – Codeforces 71B Progress Bar Solution & Explanation

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