Codeforces 32B Borze Solution & Explanation

Difficulty : 800

Problem Description

Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «–». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

Input

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It’s guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output

Output the decoded ternary number. It can have leading zeroes.

Examples

Solution

We first observe the problem statement: ‘It’s guaranteed that the given string is a valid Borze code’, which means we don’t need to worry about handling invalid inputs. We can use a simple for loop to determine how to convert the Borze code.

C# Solution

Solution1

using System.Text;

string str = Console.ReadLine();
char[]charArr = str.ToCharArray();
StringBuilder res = new StringBuilder();

for(int i=0; i<charArr.Length; i++){
    
    if(charArr[i]=='.'){
        res.Append("0");
    }
    else if(charArr[i+1]=='.'){
        res.Append("1");
        i+=1;
    }
    else{
        res.Append("2");
        i+=1;
    }
}

Console.WriteLine(res.ToString());

We also utilize StringBuilder to prevent performance degradation caused by repetitive string concatenation.

Conclusion

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The problem link : Problem – 32B – Codeforces

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